(3x=y)^2-(3x-y)^2=(3xy+1)^2-(3xy-1)^2

Question

(3x=y)^2-(3x-y)^2=(3xy+1)^2-(3xy-1)^2

Answer 1

(3x-y)²-(3x-y)²=(3xy+1)²-(3xy-1)²
9x²-6xy+y²-9x²+6xy-y²=9x²y²+6xy+1-9x²y²+6xy-1
0=12xy
x=0
y=0