Помогите пожалуйста, задание во вложениях:3

№1

$\left \{ {{3x-2y=1} \atop {4x-y=-2}} \right. \left \{ {{3x-2y=1} \atop {4x+2=y}} \right. \left \{ {{3x-2(4x+2)=1} \atop {4x+2=y}} \right. \left \{ {{3x-8x-4=1} \atop {4x+2=y}} \right. \left \{ {{-5x=5} \atop {4x+2=y}} \right. \left \{ {{x=-1} \atop {y=4*(-1)+2}} \right. \left \{ {{x=-1} \atop {y=-2,}} \right.$

y²-x²=4-1=3

№2

$\left \{ {{2x+3y=3} \atop {x-2y=5}} \right. \left \{ {{2(5+2y)+3y=3} \atop {x=5+2y}} \right. \left \{ {{10+4y+3y=3} \atop {x=5+2y}} \right. \left \{ {{7y=-7} \atop {x=5+2y}} \right. \left \{ {{y=-1} \atop {x=5+2*(-1)=3}} \right.$

x²+y²=9+1=10

№3

$\left \{ {{5x+2y=-3} \atop {x-3y=-4}} \right. \left \{ {{5(3y-4)+2y=-3} \atop {x=3y-4}} \right. \left \{ {{15y-20+2y=-3} \atop {x=3y-4}} \right. \left \{ {{17y=17} \atop {x=3y-4}} \right. \left \{ {{y=1} \atop {x=3*1-4=-1}} \right.$

x²-y²=1-1=0