8×(y+3)+4×(y-2)= 40 help

Question

8×(y+3)+4×(y-2)= 40 help

Answer 1

8y+24 +4y -8 = 40
12y +16 = 40
12y = 40-16, 12y = 24, y = 24:12, y = 2

Answer 2

8(у+3)+4(у-2)=40
8у+24+4у-8=40
12у+16=40
12у=40-16
12у=24
у=24:12
у=2
Ответ: 2