ОДЗ
(x-1)/(x+1,3)>0
x=1 x=-1,3
x∈(-∞;-1,3) U (1;∞)
1)4*2^2x-33*2^x+8≤0
2^x=a
4a²-33a+8≤0
D=1089-128=961
a1=(33-31)/8=1/4
a2=(33+31)/8=8
1/4≤a≤8⇒1/4≤2^x≤8⇒-2≤x≤3
2)log(2)[(x-1)²/(x+1,3)²*(x+1,3)²]≥2
log(2)(x-1)²≥2
2log(2)(x-1)≥2
log(2)(x-1)≥1
x-1≥2
x≥3
Ответ х=3