1) (1/7)^2x-1=49 2)2,7^х-3=1

Question

1) (1/7)^2x-1=49
2)2,7^х-3=1

Answer 1

(1/7)^(2x-1)=49
(1/7)^(2x-1)=(1/49)⁻¹
(1/7)^(2x-1)=()1/7⁻²
2x-1=-2
x=-1/2
x=-0,5

2,7^(x-3)=1
2,7^(x-3)=2,7⁰
x-3=0
x=3

Answer 2

Использованы свойства степени

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