4cos( 11π / 18 ) + 2sin( π / 9 ) / 2cos( 29π / 18 ) + sin( 10π / 9 )

Question

4cos( 11π / 18 ) + 2sin( π / 9 ) / 2cos( 29π / 18 ) + sin( 10π / 9 )

Answer 1

(4соs11π/18+2sinπ/9)/(2cos(2π-7π/18)+sin(π+π/9)=2(2cos7π/18+sinπ/9)/-2(cos7π/18+sinπ/9)=-2