44-10(3-4x)=7(5x+2) (x+4)(x+6)-x2=30 (x-1)(x-3)=(x-2)(x-4) x2-(x-5)2=10 (x-3)(x+1)=(x-2)2

Question

44-10(3-4x)=7(5x+2)

(x+4)(x+6)-x2=30

(x-1)(x-3)=(x-2)(x-4)

x2-(x-5)2=10

(x-3)(x+1)=(x-2)2

Answer 1

44-10(3-4x)=7(5x+2)

44-30+40х=35х+14

40х-35х=14-44+30

5х=0

х=0