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Решите задачу:

$(7\frac{4}{19}-2\frac{8}{19})+(8-4\frac{12}{19})=(6\frac{23}{19}-2\frac{8}{19})+(7\frac{19}{19}-2\frac{8}{19})=\\\\=4\frac{15}{19}+5\frac{11}{19}=9\frac{26}{19}=10\frac{7}{19}\\\\\\7\frac{4}{19}=6+1+\frac{4}{19}=6+\frac{19}{19}+\frac{4}{19}=6+\frac{19+4}{19}=6\frac{23}{19}\\\\8=7+1=7+\frac{19}{19}\\\\9\frac{26}{19}=9+\frac{19+7}{19}=9+\frac{19}{19}+\frac{7}{19}=9+1+\frac{7}{19}=10\frac{7}{19}$