(2у-1)(2y+1)-y(4y+3)+5y=0

Question

(2у-1)(2y+1)-y(4y+3)+5y=0

Answer 1

(2у-1)2у+1) - у(4у+3)+5у = 0
4у² - 1 - 4у² - 3у + 5у = 0
2у - 1 = 0
2у = 1
у = 0,5

Ответ: {0,5}