Решите уравнение (5×+2)^2=(5×-3)(4×+1)
25х^2 + 20x + 4 = 20x^2 - 12x + 5x - 3 25x^2 + 20x + 4 - 20x^2 +7x + 3 = 0 5x^2 + 27x + 7 = 0 D = 729 - 4*5 *7 = 729 - 140 = 589; √D ≈ 24,27 x1 = (-27 + 24,27) / 10 = - 2,63/10 = - 0,263 x2 = ( - 27 - 24,27)/10 = - 51,27/10 = - 5,127