( (a+1)/√a +1/(a -√a) -a/(√a +1) ) *(√3 -a√3)/(a+1) =
( (a+1)(a-1)+ √a +1 -a√a(√a -1)/(√a(√a -1)(√a+1) )* ( √3 (1-a)/(a +1) ) =
(a² -1+√a +1 -a²+a√a)/(√a(√a -1)(√a+1) * ( √3 (1-a)/(a +1) ) =
√a(a +1) /(√a(√a -1)(√a+1) ) *( √3 (1-a)/(a +1) ) = √3(1-a)/(a -1) = -√3.