Решите уравнение 4(x-4)(x+8)=(3x+2)(x-5)+(x-1)(x+1)
4(x-4)(x+8)=(3x+2)(x-5)+(x-1)(x+1) 4x^2+16x-128=4x^2-13x-11 4x^2+16x-128-4x^2+13x+11=0 29x=117 x=117/29 x= 4(целых) 1/29
4x²+16x-128= 3x²-13x-10+x²-1 4x²+16x-128=4x²-13x-11 4x²+16x-128-4x²+13x+11=0 29x-117=0, 29x=117, x=4.03=4