2x^2+x-4=0 a=2, b=1, c=-4 D=b^2-4ac x=-b+-кореньD/2a

Question

2x^2+x-4=0
a=2, b=1, c=-4
D=b^2-4ac
x=-b+-кореньD/2a

Answer 1

x1=(√33-1)/2*2=(√33/4)- 1/4=1,18
x2=(-√33-1)/4=-1/4=- 0,18