Представьте в виде многочлена: (m2-n3)3= (10x4-6y)3= (10a3+ 1/3b2)3= (0.1x4 - 1/2y3)3=

Решите задачу:

$(m^2-n^3)^3=m^6-3m^4n^3+3m^2n^6-n^9\\\\(10x^4-6y)^3=1000x^{12}-1800x^8y+1080x^4y^2-216y^3\\\\(10a^3+\frac{1}{3}b^2)^3=1000a^9+100a^6b^2+\frac{10}{3}a^3b^4+\frac{1}{27}b^6\\\\(0,1x^4-\frac{1}{2}y^3)^3=0,001x^{12}-\frac{3}{200}x^8y^3+\frac{3}{40}x^4y^6-\frac{1}{8}y^{27}$