Помогите решить 5.24
1) log(3) 27 - log(√3) 27 - log(1/3) 27 -log(√3/2) 64/27= =log(3) 3^3 - log(√3) (√3)^6 -log(1/3) (1/3)^(-3) - log(√3/2) (√3/2)^(-6)= =3-6-(-3)-(-6)=3-6+3+6=6