(у+4)^3+(3у+1)^3-7у^2(4у+9)=-24у^2+8

Question

(у+4)^3+(3у+1)^3-7у^2(4у+9)=-24у^2+8

Answer 1

(у+4)^3+(3у+1)^3-7у^2(4+9)  =-24у^2+8у^3+12y^2+48y+64+27y^3+27y^2+9y+1-28y^3-63y^2+24y^2-8=016y^2+57y-57=0