№ 1
а6=45
а14=-43
Найти S10
№ 2
а1=10
s14=1050
Найти: d
1) a6=a1+5d=45 a14 = a1+ 13d = -43 a1+13d-a1-5d=-43-45 8d=-88 d=-11 a1=45-5d=45+55=100 S10 = (2a1+9d)/2 * 10 = (2a1+9d)5 = (200-99)*5=101*5=505 2) S14 = (2a1+13d)/2 * 14 = (2a1+13d)*7 = 1050 (20+13d)*7=1050 20+13d = 150 13d=130 d=10