1+cosx-cosx/2=0 помогите пожалуйста
1+cosx -cos(x/2) =0 ; 2cos²(x/2) - cos(x/2) =0 ; 2cos(x/2)*( cos(x/2) -1/2) =0 ; [ cos(x/2)=0 ; cos(x/2) -1/2 =0⇒[x/2 =π/2 +πn ; x/2 =(+/-)π/3 +2πn ,n∈Z. [ x =π +2πn ; x =(+/-)2π/3 +4πn ,n∈Z.