Срочно!!!Помогите решить неравенства l3х-7l больше или равно 5,l2х-1l>5,заранее спасибо)

Решите задачу:

$|x|\ \textgreater \ a\; \; \Leftrightarrow \; \; \left [ {{x\ \textgreater \ a} \atop {x\ \textless \ -a}} \right. \; \; \; \; \; \; /////////\; (-a)----(a)///////\\\\1)\; \; |3x-7| \geq 5\; \; \to \; \; \left [ {{3x-7 \geq 5} \atop {3x-7 \leq -5}} \right. \; \left [ {{3x \geq 12} \atop {3x \leq 2}} \right. \; \left [ {{x \geq 4} \atop {x \leq \frac{2}{3}}} \right. \\\\x\in (-\infty ,\frac{2}{3}\, ]\cup [\, 4,+\infty )$

$b)\; \; |2x-1|\ \textgreater \ 5\; \; \to \; \; \left [ {{2x-1\ \textgreater \ 5} \atop {2x-1\ \textless \ -5}} \right. \; \left [ {{2x\ \textgreater \ 6} \atop {2x\ \textless \ -4}} \right. \; \left [ {{x\ \textgreater \ 3} \atop {x\ \textless \ -2}} \right. \\\\x\in (-\infty ,-2)\cup (3,+\infty )$