1+x/(x-5)-(x+3)/(x+2)≥0
[(x-5)(x+2)+x(x+2)-(x+3)(x-5)]/(x-5)(x+2)≥0
(x²-5x+2x-10+x²+2x-x²+5x-3x+15)/(x-5)(x+2)≥0
(x²+x+5)/(x-5)(x+2)≥0
x²+x+5=0
X=1-20=-19<0⇒x²+x+5>0 при любом х
x-5=0⇒x=5
x+2=0⇒x=-2
+ _ +
------------(-2)------------------(5)------------------
x<-2 U x>5 U x∈[-3;6]
x={-3;6}-2 целых решения