Вычислите: 537 4 6 -(2 8+ 12) 123 6 4-(3 5 + 8)

$4\frac{5}{6}-(2 \frac{3}{8}+\frac{7}{12})=1\frac{7}{8}$

1) $2 \frac{3}{8}+\frac{7}{12}=\frac{19}{8}+\frac{7}{12}=\frac{57+14}{24}=\frac{71}{24}=2\frac{23}{24}$

2) $4\frac{5}{6}-2\frac{23}{24}=\frac{29}{6}-\frac{71}{24}=\frac{116-71}{24}=\frac{45}{24}=\frac{15}{8}=1\frac{7}{8}$

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$6\frac{1}{4}-(3\frac{2}{5}+\frac{3}{8})=2\frac{19}{40}$

1) $3\frac{2}{5}+\frac{3}{8}=\frac{17}{5}+\frac{3}{8}=\frac{136+15}{40}=\frac{151}{40}=3\frac{31}{40}$

2) $6\frac{1}{4}-3\frac{31}{40}=\frac{25}{4}-\frac{151}{40}=\frac{250-151}{40}=\frac{99}{40}=2\frac{19}{40}$