Log2(x-2)+log2(x-3)=1

Question

Log2(x-2)+log2(x-3)=1

Answer 1

Итак, ОДЗ: х>3
log2(x-2)+log2(x-3)=log2(2)
log2(x-2)(x-3)=log2(2)
(x-2)(x-3)=2
x^2-5x+6=2
x^2-5x+4=0
x=4
x=1
по одз х=4