(a-b)(a+b)(a^2+b^2)=a^4-b^4

Question

(a-b)(a+b)(a^2+b^2)=a^4-b^4

Answer 1

(a-b)(a+b)(a²+b²)= a^{4} -b^{4}
(a²-b²)(a²+b²)= a^{4} -b^{4}
(a²)²-(b²)²= a^{4} -b^{4} 
a^{4} -b^{4}=a^{4} -b^{4}