Log1/62(2x-14)>-1/8 Помогите пожалуйста

2x>14
x>7

$log_{ \frac{1}{64} }(2x-14)\ \textless \ - \frac{1}{8} \\ 2x-14\ \textgreater \ ( \frac{1}{64} )^{- \frac{1}{8} } \\ 2x-14\ \textgreater \ (8^{-2})^{- \frac{1}{8} } \\ 2x-14\ \textgreater \ 8^{ \frac{2}{8} } \\ 2x-14\ \textgreater \ 8^{ \frac{1}{4} } \\ 2x\ \textgreater \ 14+(2^{3})^{ \frac{1}{4} } \\ 2x\ \textgreater \ 14+2^{ \frac{3}{4} } x\ \textgreater \ 7+ \frac{2^{ \frac{3}{4} }}{2} \\ x\ \textgreater \ 7+2^{ \frac{3}{4}-1 } \\ x\ \textgreater \ 7+2^{- \frac{1}{4} } \\ x\ \textgreater \ 7+ \frac{1}{ \sqrt[4]{2} }$