a) (log(1/2) 9)/(log(1/2) 27)=log(27) 9= log(3^3) 3^2=(2/3)×log(3) 3=2/3; б) 121^(1/2×log (11) 35)=121^(log(11^2) 35)=121^(log(121) 35)=35; 7) (log (3) 2 + 3log(3) 0,25)÷(log(3) 28 - log(3) 7)=(log (3) 2 + log(3) 0,25^3)÷(log(3) 28 - log(3) 7)=(log (3) 2 + log(3) 0,015625)÷(log(3) 28 - log(3) 7)=(log(3) 2×0,015625)÷(log(3) 28÷7)=(log(3) 0,03125)÷(log(3) 4)=log(4) 0,03125=log(2^2) 2^-5=-5/2 log(2) 2=-2,5.