2sin π/6+5ctg^2 π/4+tg π/4+6cos π/6

Question

2sin π/6+5ctg^2 π/4+tg π/4+6cos π/6

Answer 1

2*(1/2)+5*(1)^2+1+6*(√3/2)= 1+5+1+3√3 = 7+3√3