помогите пожалуйста решить неравенство log1/3 (3x-1) >-1 ( 1/3 -основание )
-1;" alt="log_{\frac{1}{3}}(3x-1)>-1;" align="absmiddle" class="latex-formula"> 0}} \right." alt="\left \{ {{3x-1<(\frac{1}{3})^{-1}} \atop {3x-1>0}} \right." align="absmiddle" class="latex-formula"> 0}} \right." alt="\left \{ {{3x-1<3} \atop {3x-1>0}} \right." align="absmiddle" class="latex-formula"> 1}} \right." alt="\left \{ {{3x<4} \atop {3x>1}} \right." align="absmiddle" class="latex-formula"> \frac{1}{3}}} \right." alt="\left \{ {{x<\frac{4}{3}} \atop {x>\frac{1}{3}}} \right." align="absmiddle" class="latex-formula"> Ответ: x ∈ (1/3; 4/3;).