10y/9y2-4+y-5/3y+2=y-3/2-3y решение ПОМОГИТЕ

Question

10y/9y2-4+y-5/3y+2=y-3/2-3y решение ПОМОГИТЕ

Answer 1

10y/(3y-2)(3y+2)+(y-5)/(3y+2)+(y-3)/(3y-2)=0
y≠2/3 U y≠-2/3
10y+(y-5)(3y-2)+(y-3)(3y+2)=0
10y+3y²-2y-15y+10+3y²+2y-9y-6=0
6y²-14y+4=0
3y²-7y+2=0
D=49-24=25
y1=(7-5)/6=1/3
y2=(7+5)/6=2