lim x→0 (8x^3 - 2x^2 + 1) / (4x^3 + 3x^2 - 1)

Question

lim x→0 (8x^3 - 2x^2 + 1) / (4x^3 + 3x^2 - 1)

Answer 1

0} \frac{8x^3-2x^2+1}{4x^3+3x^2-1}=\\ lim_{x->0} \frac{8-\frac{2}{x}+\frac{1}{x^3}}{4+\frac{3}{x}-\frac{1}{x^3}}=\\ \frac{8-0+0}{4+0-0}=2" alt="lim_{x->0} \frac{8x^3-2x^2+1}{4x^3+3x^2-1}=\\ lim_{x->0} \frac{8-\frac{2}{x}+\frac{1}{x^3}}{4+\frac{3}{x}-\frac{1}{x^3}}=\\ \frac{8-0+0}{4+0-0}=2" align="absmiddle" class="latex-formula">