1)
sinx - √3 cosx = 0
cosx cosx cosx
tgx - √3=0
tgx=√3
x=π/3 + πn, n∈Z
2) sin²x - 3sinx cosx +2cos²x = 0
cos²x cos²x cos²x cos²x
tg²x - 3tgx +2 =0
Замена y=tgx
y²-3y+2=0
D=9-8=1
y₁=3-1 =1
2
y₂=3+1 =2
2
При у=1
tgx=1
x=π/4 +πn, n∈Z
При у=2
tgx=2
x=arctg2+πn, n∈Z