0;\\\\y^2-15=2y;\\\\y^2-2y-15=0;\\\\y^2-5y+3y-15=0;\\\\y(y-5)+3(y-5)=0;\\\\(y+3)(y-5)=0;\\\\y+3=0;y_1=-3<0;\\\\y-5=0;y_2=5;y=5;\\\\x^2+1=5;\\\\x^2=5-1=4;\\\\x_1=-\sqrt{4}=-2;\\\\x_2=\sqrt{4}=2" alt="(x^2+1)^2-15=2x^2+2;\\\\(x^2+1)^2-15=2(x^2+1);\\\\x^2+1=y>0;\\\\y^2-15=2y;\\\\y^2-2y-15=0;\\\\y^2-5y+3y-15=0;\\\\y(y-5)+3(y-5)=0;\\\\(y+3)(y-5)=0;\\\\y+3=0;y_1=-3<0;\\\\y-5=0;y_2=5;y=5;\\\\x^2+1=5;\\\\x^2=5-1=4;\\\\x_1=-\sqrt{4}=-2;\\\\x_2=\sqrt{4}=2" align="absmiddle" class="latex-formula">
ответ: -2; 2