3log 1000 10 log36 216 - log 49 1/7 log h^12 h^6 + log h d - 1/3 log h a log x 1/216...

Question

3log 1000 10 log36 216 - log 49 1/7
log h^12 h^6 + log h d - 1/3 log h a
log x 1/216 =-2
log0,04 125=x
log x 0,81 = -2
log 1/8 1/64

Answer 1

3lg(10³)10*log(6²)6³-log(7²)(7^-1)=3*1/3*3/2-(-1/2)=3/2+1/2=2

log(h^12)(h^6)+log(h)(d/∛a)=1/2+log(h)(d/∛a)

log(x)1/216=2
x²=1/6³
x=-1/6√6
x=1/6√6

log((1/5)²)((1/5)^-3)=-3/2
x=-1,5

log(x)(9/10)²=-2
x^-2=(9/10)²
x²=(10/9)²
x=10/9=1 1/9

log((1/2)³(((1/2)^5)=5/3=1 2/3