Ctg x = 2,05 sin²x = 1 cos²x = 1/2
1)ctgx=2,05⇒x=arcctg2,05+πn,n∈z 2)sin²=1 (1-cos2x)/2=1 1-cos2x=2 cos2x=-1 2x=π+2πn,n∈z x=π/2+πn,n∈z 3)cos²x=1/2 (1+cos2x)/2=1/2 1+cos2x=1 cos2x=0 2x=π/2+πn,n∈z x=π/4+πn/2,n∈z