Решите систему уравнений методом подстановки 5х-3у=14 2х+у=10

Решите задачу:

$\left \{ {{5x-3y=14,} \atop {2x+y=10;}}\right. \left \{ {{5x-3(10-2x)=14,} \atop {y=10-2x;}}\right. \left \{ {{5x-30+6x=14,} \atop {y=10-2x;}}\right. \left \{ {{11x=14+30,} \atop {y=10-2x;}}\right. \left \{ {{11x=44,} \atop {y=10-2x;}}\right.$
$\left \{ {{x=\frac{44}{11},} \atop {y=10-2x;}}\right. \left \{ {{x=4,} \atop {y=10-2\cdot4;}}\right. \left \{ {{x=4,} \atop {y=10-8;}}\right. \left \{ {{x=4,} \atop {y=2.}}\right.$