(lg81+lg64)/(2lg3+2lg2)

Question

(lg81+lg64)/(2lg3+2lg2)

Answer 1

(lg81+lg64)/(2lg3+2lg2)=lg(9²*8²)/(2lg(2*3))=2lg(9*8)/(2lg(3*2)=
=lg72/lg6=lg(72-6)=lg66.