ОДЗ: х≠4
(x+1)² - 1 ≤ 0
(4-x)² 4
4(x+1)² - (4-x)² ≤0
4(4-x)²
(2(x+1))² - (4-x)² ≤ 0
4(4-x)²
(2(x+1)-(4-x))(2(x+1)+4-x) ≤ 0
4(4-x)²
(2x+2-4+x)(2x+2+4-x) ≤ 0
4(4-x)²
(3x-2)(x+6) ≤ 0
4(-(x-4))²
3(x - ²/₃) (x+6) ≤ 0
4(x-4)²
(x- ²/₃)(x+6) ≤ 0
(x-4)²
(x-²/₃)(x+6)(x-4)² ≤ 0
x=²/₃ x= -6 x=4
+ - + +
--------- -6 ------------- 2/3 ------------ 4 -----------
\\\\\\\\\\\\\\\\
x∈[-6; 2/3]