Решите номер 35.Есть вложение.

Решите задачу:

$\log_2(x+3)-2\log_24\ \textgreater \ 0, \ x+3\ \textgreater \ 0; \ x\ \textgreater \ -3 \\\ \log_2(x+3)-2\cdot2\ \textgreater \ 0 \\\ \log_2(x+3)-4\ \textgreater \ 0 \\\ \log_2(x+3)\ \textgreater \ 4 \\\ x+3\ \textgreater \ 2^4 \\\ x+3\ \textgreater \ 16 \\\ x\ \textgreater \ 13 \\\ x\in(13;+\infty)$

$\log_2(x+3)-2\log_24\ \textgreater \ 0, \ x+3\ \textgreater \ 0; \ x\ \textgreater \ -3 \\\ \log_2(x+3)-\log_24^2\ \textgreater \ 0 \\\ \log_2(x+3)-\log_216\ \textgreater \ 0 \\\ \log_2 \frac{x+3}{16} \ \textgreater \ 0 \\\ \frac{x+3}{16}\ \textgreater \ 2^0 \\\ \frac{x+3}{16}\ \textgreater \ 1 \\\ x+3\ \textgreater \ 16 \\\ x\ \textgreater \ 13 \\\ x\in(13;+\infty)$