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Решите задачу:

$\frac{4^{x}}{4^{x}-3^{x}} \ \textless \ 4\; ;\; ODZ:\; 4^{x}-3^{x}\ne 0\; ,\; x\ne 0\\\\\frac{4^{x}-4(4^{x}-3^{x})}{4^{x}-3^{x}}\ \textless \ 0\; ;\; \; \frac{4\cdot 3^{x}-3\cdot 4^{x}}{4^{x}-3^{x}}\ \textless \ 0\; |\frac{:3^{x}}{:3^{x}}\\\\\frac{4-3\cdot (\frac{4}{3})^{x}}{(\frac{4}{3})^{x}-1}\ \textless \ 0\; ;\; \; t=(\frac{4}{3})^{x}\; \to \; \; \frac{4-3t}{t-1}\ \textless \ 0\\\\\frac{3t-4}{t-1}\ \textgreater \ 0\; ,\; \; +++(1)---(\frac{4}{3})+++\; \; \left [ {{t\ \textless \ 1} \atop {t\ \textgreater \ \frac{4}{3}}} \right. \\\\a)\; (\frac{4}{3})^{x}\ \textless \ 1\; ,\; \; (\frac{4}{3})^{x}\ \textless \ (\frac{4}{3})^0\; ,\; x\ \textless \ 0$

$b)\; \; (\frac{4}{3})^{x}\ \textgreater \ \frac{4}{3}\; ,\; x\ \textgreater \ 1\\\\x\in (-\infty ,0)\cup (1,+\infty )$