4.
а) 5x+1<0<br> x-2
ОДЗ: х ≠ 2
(5x+1)(x-2) <0<br>5(x+ ¹/₅)(x-2)<0<br>(x+ ¹/₅)(x-2)<0<br>x= -¹/₅ x=2
+ - +
------- -1/5 --------- 2 -------------
\\\\\\\\\\\\\
x∈(-1/5; 2)
б) 3x-1 ≥2
x+8
ОДЗ: х≠ -8
3x-1 - 2(x+8) ≥0
x+8
3x-1-2x-16 ≥ 0
x+8
x-17 ≥0
x+8
(x-17)(x+8) ≥ 0
x=17 x= -8
+ - +
-------- -8 ------------ 17 -------------
\\\\\\\\\ \\\\\\\\\\\\\\\
x∈(-∞; -8)U[17; +∞)