Решите пожалуйста систему уравнений

$\left \{ {{ \frac{6}{x+y}+ \frac{5}{x-y}=7 } \atop { \frac{3}{x+y} }- \frac{2}{x-y}=-1 } \right.$

$\left \{ {{ \frac{6(x-y)+5(x+y)}{(x-y)(x+y)} =7} \atop { \frac{3(x-y)-2(x+y)}{(x-y)(x+y)} }=-1} \right.$

$\left \{ {{11x-y=7( x^{2} - y^{2}) } \atop {7(5y-x)= 7(x^{2} - y^{2}) }} \right.$

$11x-y=35y-7x$
$18x-36y=0$
$x=2y$ => $\frac{6}{3y}+ \frac{5}{y} = 7$
$3y=3 =\ \textgreater \ y = 1; x=2$