Помогите, решить систему!

$\left \{ {{2\cdot 3^{x-1}+7\cdot 5^{y+1}=37} \atop {9^{x}+5^{y}=10}} \right. \; \left \{ {{\frac{2}{3}\cdot 3^{x}+7\cdot 5\cdot 5^{y}=37} \atop {5^{y}=10-9^{x}}} \right. \; \left \{ {{\frac{2}{3}\cdot 3^{x}+35\cdot (10-3^{2x})=37} \atop {5^{y}=10-3^{2x}}} \right. \\\\\frac{2}{3}\dcot 3^{x}+350-35\cdot 3^{2x}-37=0\, |\cdot 3\\\\105\cdot 3^{2x}-2\cdot 3^{x}-939=0\; ;\; \; t=3^{x}\ \textgreater \ 0\\\\105t^2-2t-939=0\\\\D/4=1+98595=98596\; ;\; \sqrt{D/4}=314\\\\t_1=\frac{1-314}{105}=-\frac{313}{105}<0$

$t_2=\frac{315}{105}=3;\\\\3^{x}=3;x=1\\\\5^{y}=10-3^2=1\\\\5^{y}=5^0;y=0$

Ответ: (1;0).