Заранее спасибо! решите систему {x/2=y/3 {x+y=4

$\left \{ {{ \frac{x}{2}= \frac{y}{3} } \atop {x+y=4}} \right. \\ \\ \left \{ {{3x=2y} \atop {x+y=4}} \right. \\ \\ \left \{ {{x=4-y} \atop {3(4-y)=2y}} \right. \\ \\ \left \{ {{x=4-y} \atop {12-3y=2y}} \right. \\ \\ \left \{ {{x=4-y} \atop {5y=12}} \right. \\ \\ \left \{ {{x=4-y} \atop {y= \frac{12}{5} }} \right. \\ \\ \left \{ {{y= \frac{12}{5} } \atop {x= \frac{8}{5} }} \right.$

Ответ: $( \frac{8}{5} ; \frac{12}{5} )$