√(2-log(x)16)=-2*√3/log(4)x
√(2-log(x)4²)=-2*√3*log(x)4
(√(2-2*log(x)4))²=(-2*√3*log(x)4)²
2-2*log(x)4=12*(log(x)4)²
log(x)4=v ⇒
12v+2v-2=0 D=100 √D=10
v₁=1/3 v₂=-1/2
log(x)4=1/3 x^(1/3)=4 x₁=∛4
log(x)4=-1/2 x^(-1/2)=4 x₂=1/16.
√(log₃x)+log₃x=6
log₃x=v
v²+v-6=0 D=25
v₁=-3 v₂=2
log₃x=-3 x=3⁻³=1/27
log₃x=2 x=3²=9.