1) =7
2) [tex]\frac{n^{3}+4n^{2}}{n^{2}-16}= \frac{n^{2}(n+4)}{(n-4)(n+4)} = \frac{n^{2}}{n-4}" alt="\frac{2}{9}[\tex]
2) [tex]\frac{n^{3}+4n^{2}}{n^{2}-16}= \frac{n^{2}(n+4)}{(n-4)(n+4)} = \frac{n^{2}}{n-4}" align="absmiddle" class="latex-formula">
3) x =1