2sin(7п/2-х)*sinx=cosx помогите решить
2sin(2n+3π/2-x)*sinx=cosx 2sin(3π/2+x)sinx=cosx -2cosxsinx=cosx cosx+2cosxsinx=0 cosx(1+2sinx)=0 cosx=0⇒x=π/2+ππn,n∈Z sinx=-1/2⇒x=(-1)^(k+1)π/6+πk,k∈Z