По II З.Н
ma = mg + Fтр + N
ox: ma = - Fтр
oy: N = mg
ma = -umg
a = -ug
u = a/g
S = (V+V0)*t/2
V = 0 m/s
V0 = 2S/t = 4/6 = 2/3 m/s
V = V0 - at
V0 = at
a = V0/t = 2/3(*6) = 1/9 m/s^2
ma = -Fтр
30/9 = Fтр
Fтр = 10/3 Н
umg = 10/3
u = 10/900 = 1/90
Otvet: u = 1/90, Fтр = 10/3 H