Решить уравнение (2t-3)(5t+2)+(3t-1)(4t+2)=10t²-5

Question

Решить уравнение (2t-3)(5t+2)+(3t-1)(4t+2)=10t²-5

Answer 1

(2t-3)*(5t+2) +(3t-1)*(4t+2)=10t^2-5
10t^2-15t+4t-6+(12t^2-4t+6t-2)=10t^2-5
22t^2-9t-8=10t^2-5
12t^2-9t-8+5=0
12t^2-9t-3=0
4t^2-3t-1=0
D=9-4*4*(-1)=9+8=17
t1=3-√17\8
t2=3+√17\8