Сравнить значения выражений:

$0,35^{8} \ \textless \ 1, (-5,4)^{8}= 5,4^{8}\ \textgreater \ 1$ значит $0,35^{8}\ \textless \ (-5,4)^{8}$
< <img src="https://tex.z-dn.net/?f=+%5Cfrac%7B11%7D%7B17%7D%3D+%5Cfrac%7B143%7D%7B221%7D++%5C+%5Ctextgreater+%5C++%5Cfrac%7B6%7D%7B13%7D%3D+%5Cfrac%7B102%7D%7B221%7D%2C+%28+%5Cfrac%7B11%7D%7B17%7D%29%5E%7B5%7D%5C+%5Ctextgreater+%5C+%28+%5Cfrac%7B6%7D%7B13%7D%29%5E%7B5%7D%2C+-%28+%5Cfrac%7B11%7D%7B17%7D%29%5E%7B5%7D%5C+%5Ctextless+%5C+-%28+%5Cfrac%7B6%7D%7B13%7D%29%5E%7B5%7D+" id="TexFormula4" title=" \frac{11}{17}= \frac{143}{221} \ \textgreater \ \frac{6}{13}= \frac{102}{221}, ( \frac{11}{17})^{5}\ \textgreater \ ( \frac{6}{13})^{5}, -( \frac{11}{17})^{5}\ \textless \ -( \frac{6}{13})^{5} " alt=" \frac{11}{17}= \frac{143}{221} \ \textgreater \ \frac{6}{13}= \frac{102}{221}, ( \frac{11}{17})^{5}\ \textgreater \ ( \frac{6}{13})^{5}, -( \frac{11}{17})^{5}\ \textless \ -( \frac{6}{13})^{5} " align="absmiddle" class="latex-formula">
< <img src="https://tex.z-dn.net/?f=1-+%5Csqrt%7B5%7D%5C+%5Ctextless+%5C+0%2C+%281-+%5Csqrt%7B5%7D%29%5E%7B7%7D%5C+%5Ctextless+%5C+0%2C++%5Csqrt%7B3%7D-1%5C+%5Ctextgreater+%5C+0%2C+%28+%5Csqrt%7B3%7D-1%29%5E%7B2%7D%5C+%5Ctextgreater+%5C+0++++++" id="TexFormula5" title="1- \sqrt{5}\ \textless \ 0, (1- \sqrt{5})^{7}\ \textless \ 0, \sqrt{3}-1\ \textgreater \ 0, ( \sqrt{3}-1)^{2}\ \textgreater \ 0 " alt="1- \sqrt{5}\ \textless \ 0, (1- \sqrt{5})^{7}\ \textless \ 0, \sqrt{3}-1\ \textgreater \ 0, ( \sqrt{3}-1)^{2}\ \textgreater \ 0 " align="absmiddle" class="latex-formula">
< <img src="https://tex.z-dn.net/?f=+%5Csqrt%7B3%7D%2B1%5C+%5Ctextless+%5C++%5Csqrt%7B2%7D%2B2%2C++%28%5Csqrt%7B3%7D%2B1%29%5E%7B10%7D+%5C+%5Ctextless+%5C++%28%5Csqrt%7B2%7D%2B2%29%5E%7B10%7D+++" id="TexFormula6" title=" \sqrt{3}+1\ \textless \ \sqrt{2}+2, (\sqrt{3}+1)^{10} \ \textless \ (\sqrt{2}+2)^{10} " alt=" \sqrt{3}+1\ \textless \ \sqrt{2}+2, (\sqrt{3}+1)^{10} \ \textless \ (\sqrt{2}+2)^{10} " align="absmiddle" class="latex-formula">