a) tqα +ctqα =3 ;
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(tq²α +ctq²α) - ?
tq²α +ctq²α =(tqα +ctqα)² -2tqαctqα =3² -2 =7.
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) tqα = -3
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(3sinα -4cosα)/(5sinα +6cosα) - ?
(3sinα -4cosα)/(5sinα +6cosα) =cosα(3tqα -4)/cosα(5tqα +6) =
(3tqα -4)/(5tqα +6) =(3(-3) -4)/(5(-3) +6) =13/9. * * * =1 4/9 * * *