Помогите решить 1.(в-4)^2+(в-1)(2-в) 2.(5+2у)(у-3)-(5-2у)^2
1. (в-4)²+(в-1)(2-в)=в²-8в+16+2в-2-в²+в=14-5в 2. (5+2у)(у-3)-(5-2у)²=5у+2у²-15-6у-25+20у-4у²=-2у²+19у-40